By Pantelis Aravogliadis, Vasilis Vassalos (auth.), Abdelkader Hameurlain, Stephen W. Liddle, Klaus-Dieter Schewe, Xiaofang Zhou (eds.)
This publication constitutes the refereed court cases of the 22 overseas convention on Database and professional platforms purposes, DEXA 2011, held in Toulouse, France, August 29 - September 2, 2011. The fifty two revised complete papers and forty brief papers awarded have been conscientiously reviewed and chosen from 207 submissions. The papers are equipped in topical sections on XML querying and perspectives; information mining; queries and seek; semantic internet; details retrieval; company purposes; consumer aid; indexing; queries, perspectives and information warehouses; ontologies; actual facets of databases; layout; distribution; miscellaneous topics.
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Extra info for Database and Expert Systems Applications: 22nd International Conference, DEXA 2011, Toulouse, France, August 29 - September 2, 2011, Proceedings, Part II
Let p, q be queries in XP (/, , ∗), such that the C-satisfying set for q R = ∅. Then p ⊇SAT (D) q if and only if p ⊇SAT (C) q. Proof. (if) Assume p ⊇SAT (C) q then p ⊇SAT (D) q, because SAT (C) ⊇ SAT (D). (only if) Assume p ⊇SAT (D) q but p ⊇SAT (C) q. We will derive a contradiction. Since there is an embedding from q to every t ∈ R and p ⊇SAT (D) q, then there is also an embedding from p to every tree t ∈ R. If p ⊇SAT (C) q then by lemma 2 there is no homomorphism from p to chaseC (q). We have the following two cases: Case A: a single path in p fails to map to any path in chaseC (q) : There is a node x in p with parent y, such that y is mapped to a node in chaseC (q) but no mapping from x to any node in chaseC (q) exists.
Stars in the inverted view signify that the view itself is a surjective function, so that we may not be able to reconstruct the complete database from the view. As we will show next, when our framework synthesizes the incremental view updates, the results of the inverted view must always pass through the view function to derive a view-to-view function, which eliminates the star values. To show that view(view’($V)) is indeed equal to $V, we have to use normalization rules and the properties of the key constraints.
Then, Rule (10) becomes: Ix (for $v in e1 return e2 , y) = Ix (e1 , for $v in y return unify(Iv (e2 , $v ), IV[v])) (10’) Also note that Rule (10) can only apply if the loop body is not of a sequence type. For example, it cannot invert y = for $v in x return ($v,$v+1). )] return e2 , y) (11) Inverting an equality predicate, y = e[e1 = e2 ], could be as easy as inverting y = e. The equality e1 = e2 though may give us more information about the inverse code since it relates data produced by two different places in the view code.